2y^2=26y

Solution for 2y^2=26y equation:

2y^2=26y

We move all terms to the left:

2y^2-(26y)=0

a = 2; b = -26; c = 0;
Δ = b2-4ac
Δ = -262-4·2·0
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-26}{2*2}=\frac{0}{4}
=0
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+26}{2*2}=\frac{52}{4}
=13
$